Ajax Image upload Working Code

$(function (e) {
    $('#imgUploadForm').on('submit',(function(event) {
        event.preventDefault();
        var formData = new FormData(this);

        $.ajax({
            type:'POST',
            url: $(this).attr('action'),
            data:formData,
            cache:false,
            contentType: false,
            processData: false,
            success:function(data){
                console.log("success");
                console.log(data);
            },
            error: function(data){
                console.log("error");
                console.log(data);
            }
        });
    }));

    $("#ImageBrowseField").on("change", function() {
        $("#imageUploadForm").submit();
    });
});

Here is the form

<form name="photo" id="imgUploadForm" enctype="multipart/form-data" action="<?php echo $_SERVER["PHP_SELF"];?>" method="post">
    <input type="file" style="widows:0; height:0" id="ImageBrowseField" hidden="hidden" name="image" size="30"/>
    <input type="submit" name="upload" value="Upload" />
    <img width="100" style="border:#000; z-index:1;position: relative; border-width:2px; float:left" height="100px" src="<?php echo $upload_path.$large_image_name.$_SESSION['user_file_ext'];?>" id="thumbnail"/>
</form>

Hoping it helps